Find the

Find the pressure exerted by a crawler tractor of mass 30 t standing on a horizontal road if the content of the contact surface of the belts with the ground is 6 m square.

Correct answer:

p =  49050 Pa

Step-by-step explanation:

$$\begin{gathered} m=30\text{ t}\to \text{ kg}=30\cdot 1000\text{ kg}=30000\text{ kg } \\ S=6{\text{m}}^2 \\ g=9.81{\text{m/s}}^2 \\ F=m\cdot g=30000\cdot 9.81=294300\text{ N } \\ p=F\mathrm{/}S=294300\mathrm{/}6=49050\text{ Pa} \end{gathered}$$

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