Find the

Find the pressure exerted by a crawler tractor of mass 30 t standing on a horizontal road if the content of the contact surface of the belts with the ground is 6 m square.

Correct result:

p =  49050 Pa

Solution:

m=30 t kg=30 1000  kg=30000 kg S=6 m2 g=9.81 m/s2  F=m g=30000 9.81=294300 N  p=F/S=294300/6=49050 Pa



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