Five pumps

Three same pumps fill the tank with 50400 liters of diesel in 7 hours. How many liters of diesel will it take in 4 hours if we add two more of the same pumps and pump them the same way?

How much more (or less) will they get if we add 2 of the same pumps and all work for 4 hours?

Result

V1 =  48000 l
d =  -2400 l

Solution:

V0=50400 l  Q=50400/7/3=2400 l/h  V1=4⋅ (3+2)⋅ Q=4⋅ (3+2)⋅ 2400=48000=48000  l V_{ 0 } = 50400 \ l \ \\ \ \\ Q = 50400/7/3 = 2400 \ l/h \ \\ \ \\ V_{ 1 } = 4 \cdot \ (3+2) \cdot \ Q = 4 \cdot \ (3+2) \cdot \ 2400 = 48000 = 48000 \ \text{ l }
d=V1−V0=48000−50400=−2400=−2400  l d = V_{ 1 } - V_{ 0 } = 48000 - 50400 = -2400 = -2400 \ \text{ l }

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