Five pumps

Three same pumps fill the tank with 50400 liters of diesel in 7 hours. How many liters of diesel will it take in 4 hours if we add two more of the same pumps and pump them the same way?

How much more (or less) will they get if we add 2 of the same pumps and all work for 4 hours?

Correct result:

V1 =  48000 l
d =  -2400 l

Solution:

V0=50400 l  Q=50400/7/3=2400 l/h  V1=4⋅ (3+2)⋅ Q=4⋅ (3+2)⋅ 2400=48000 lV_{0}=50400 \ \text{l} \ \\ \ \\ Q=50400/7/3=2400 \ \text{l/h} \ \\ \ \\ V_{1}=4 \cdot \ (3+2) \cdot \ Q=4 \cdot \ (3+2) \cdot \ 2400=48000 \ \text{l}
d=V1−V0=48000−50400=−2400 ld=V_{1} - V_{0}=48000 - 50400=-2400 \ \text{l}

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