Aquarium wet walls

The aquarium has the shape of a block with dimensions a = 40 cm, b = 15 cm, c = 30 cm. The aquarium is two-thirds full of water. Calculate the area of wet walls of the aquarium.

Final Answer:

S =  2200 cm²

Step-by-step explanation:

$$\begin{gathered} a=40\text{cm} \\ b=15\text{cm} \\ c=30\text{cm} \\ {c}_2=\frac{2}{3}\cdot c=\frac{2}{3}\cdot 30=\frac{2\cdot 30}{3}=\frac{60}{3}=20\text{cm} \\ o=2\cdot (a+b)=2\cdot (40+15)=110\text{cm} \\ S=o\cdot c_2=110\cdot 20=2200{\text{cm}}^2 \end{gathered}$$

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