Find the 21

Find the sum of the six terms of the finite geometric sequence 96, -48, 24, -12

Correct result:

s =  63

Solution:

a1=96 a2=48  q=a2/a1=(48)/96=12=0.5  a3=q a2=(0.5) (48)=24 a4=q a3=(0.5) 24=12 a5=q a4=(0.5) (12)=6 a6=q a5=(0.5) 6=3  s=a1+a2+a3+a4+a5+a6=96+(48)+24+(12)+6+(3)=63



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