Sides of triangle

Triangle has circumference 42 cm. Side a is 2 times shorter than side b and sice c is 2 cm longer than side a. Determine the sizes of sides of a triangle.

Result

a =  16
b =  8
c =  18

Solution:


a+b+c=42
a=2b
c = a+2

a+b+c = 42
a-2b = 0
a-c = -2

a = 16
b = 8
c = 18

Calculated by our linear equations calculator.







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To solve this verbal math problem are needed these knowledge from mathematics:

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