Sum of three numbers

The sum of three numbers from which second number is 20% smaller than the first number and the third number is 25% smaller than the second number is 96. Determine this numbers.

Correct result:

x =  40
y =  32
z =  24

Solution:


x+y+z=96
y=x-0.20x
z=y-0.25y

x+y+z=96
y=x-0.20•x
z=y-0.25•y

x+y+z = 96
0.8x-y = 0
0.75y-z = 0

x = 40
y = 32
z = 24

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