The car

A car travelled the distance from A to B in four hours. If the average speed is increased by 17 km/h, the car covers the same distance one hour sooner. Determine the initial speed of the car and the distance between A and B.

Final Answer:

v =  51 km/h
s =  204 km

Step-by-step explanation:

$$\begin{gathered} t=4\text{h} \\ s=v\cdot t \\ s=(v+17)\cdot (t-1) \\ v\cdot t=(v+17)\cdot (t-1) \\ v\cdot 4=(v+17)\cdot (4-1) \\ v=51=51\text{km/h} \end{gathered}$$

$s=v\cdot t=51\cdot 4=204\text{km}$

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