# First man

What is the likelihood of a random event where are five men and seven women first will leave the man?

Correct result:

p =  0.4167

#### Solution:

$p=5\mathrm{/}\left(5+7\right)=\frac{5}{12}=0.4167$ We would be pleased if you find an error in the word problem, spelling mistakes, or inaccuracies and send it to us. Thank you! Tips to related online calculators
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