First man

What is the likelihood of a random event where are five men and seven women first will leave the man?

Result

p =  0.417

Solution:

p=5/(5+7)=512≐0.4167≐0.417p=5/(5+7)=\dfrac{ 5 }{ 12 } \doteq 0.4167 \doteq 0.417

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