Regular 4-sided pyramid

Find the area (surface area) of a regular 4-sided pyramid if its height is 20 m and the wall height is 23 m.

Correct result:

S =  1560.9191 m2

Solution:

h=20 m h2=23 m  (a/2)2+h2=h22=232=529  a=2⋅ h22−h2=2⋅ 232−202=2 129 m≐22.7156 m  S1=a2=22.71562=516 m2 S2=a⋅ h22=22.7156⋅ 232=23 129 m2≐261.2298 m2  S=S1+4⋅ S2=516+4⋅ 261.2298=1560.9191 m2

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