Sum of fall dices

What is the probability that the sum of 9 will fall on a roll of two dice?

Hint: write down all the pairs that can occur as follows:
11 12 13 14 15. .
21 22 23 24. .. .
31 32. ..
. .
. . . .. . 66, count them, it's the variable n

variable m: 36, 63,. .. . write it down and count it and substitute it into the formula

Correct answer:

p =  0.1111

Step-by-step explanation:

$$\begin{gathered} n=6\cdot 6=36 \\ 3+6;4+5;5+4;6+3 \\ m=4 \\ p={\displaystyle \frac{m}{n}}={\displaystyle \frac{4}{36}}={\displaystyle \frac{1}{9}}=0.1111 \end{gathered}$$

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