Chess

How many ways can select 4 fields on a classic chessboard with 64 fields so that fields don't have the same color?

Correct answer:

n =  952320

Step-by-step explanation:

$n=32\cdot 32\cdot (32-1)\cdot (32-2)=952320$

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Showing 2 comments:

Mathfun

Picking 4 out of 64 is 64*63*62*61/4! = 635,376
This answer seem way too big

2 years ago  Like

Mathfun

My attempt Pick 4 out of 64, 635,376 ways
Pick 4 of the same color is 2*32*31*30*29 / 4! = 71,920
Subtract the two is ways not all 4 are same color = 563,456

2 years ago  Like

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