# Chess

How many ways can select 4 fields on classic chess board with 64 fields, so that fields don't has the same color?

Result

n =  952320

#### Solution:

$n = 32 \cdot \ 32 \cdot \ (32-1) \cdot \ (32-2) = 952320$

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Leave us a comment of this math problem and its solution (i.e. if it is still somewhat unclear...):

Mathfun
Picking 4 out of 64 is 64*63*62*61/4! = 635,376
This answer seem way too big

Mathfun
My attempt Pick 4 out of 64, 635,376 ways
Pick 4 of the same color is 2*32*31*30*29 / 4! = 71,920
Subtract the two is ways not all 4 are same color = 563,456

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