Nut distribution

Alena, Andrej, and George have a total of 74 nuts. Alena has 45% more nuts than Andrej, and George has 5 more nuts than Andrej. Determine how many nuts Alena, George, and Andrej have.

Final Answer:

a =  29
b =  20
c =  25

Step-by-step explanation:


a+b+c=74
a = 1.45 b
c = 5 + b

a+b+c=74
a = 1.45·b
c = 5 + b

a+b+c = 74
a-1.45b = 0
b-c = -5

Row 2 - Row 1 → Row 2
a+b+c = 74
-2.45b-c = -74
b-c = -5

Row 3 - 1/-2.45 · Row 2 → Row 3
a+b+c = 74
-2.45b-c = -74
-1.408c = -35.204


c = -35.20408163/-1.40816327 = 25
b = -74+c/-2.45 = -74+25/-2.45 = 20
a = 74-b-c = 74-20-25 = 29

a = 29
b = 20
c = 25

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