Leaking swimming pool

Between 10 P. M. and 7:10 A. M. , the water level in a swimming pool decreased by 5/12 inches . Assuming that the water level decreased at a constant rate, how much did the water level drop each hour?

Correct result:

h =  0.1471 inch/h

Solution:

$$\begin{gathered} t=10.00-7{\displaystyle \frac{10}{60}}\doteq 2.8333\text{ h } \\ H={\displaystyle \frac{5}{12}}\doteq 0.4167\text{ inch } \\ h=H\mathrm{/}t=0.4167\mathrm{/}2.8333={\displaystyle \frac{5}{34}}=0.1471\text{ inch/h} \end{gathered}$$

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