Water level

How high is the water in the swimming pool with dimensions of 37m in length and 15m in width, if an inlet valve is opened for 10 hours flowing 12 liters of water per second?

Result

x =  0.778 m

Solution:

a=37 m b=15 m S=a⋅ b=37⋅ 15=555 m3  t=10⋅ 3600=36000 s V=t⋅ 12=36000⋅ 12=432000 l  V1=V→m3=V/1000 m3=432 m3  x=V1/S=432/555≐144185≐0.7784≐0.778 ma=37 \ \text{m} \ \\ b=15 \ \text{m} \ \\ S=a \cdot \ b=37 \cdot \ 15=555 \ \text{m}^3 \ \\ \ \\ t=10 \cdot \ 3600=36000 \ \text{s} \ \\ V=t \cdot \ 12=36000 \cdot \ 12=432000 \ \text{l} \ \\ \ \\ V_{1}=V \rightarrow m^3=V / 1000 \ m^3=432 \ m^3 \ \\ \ \\ x=V_{1}/S=432/555 \doteq \dfrac{ 144 }{ 185 } \doteq 0.7784 \doteq 0.778 \ \text{m}

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