Three children

3 children eat 8 chocolates in 6 days. How many chocolates 6 children eat in 18 days?

Result

n =  48

Solution:

d=8/6/3=490.4444 n=6 18 d=6 18 0.4444=48d=8/6/3=\dfrac{ 4 }{ 9 } \doteq 0.4444 \ \\ n=6 \cdot \ 18 \cdot \ d=6 \cdot \ 18 \cdot \ 0.4444=48



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