# Angle between lines

Calculate the angle between these two lines:

$p:-8x+4y+5=0$

$q:10x+10y-7=0$

Correct result:

α =  45 °

#### Solution:

$\alpha =\mathrm{arctan}\left(\frac{\mathrm{\mid }\frac{-8}{4}-\frac{10}{10}\mathrm{\mid }}{\mathrm{\mid }1-\frac{-8}{4}\cdot \frac{10}{10}\mathrm{\mid }}\right)=4{5}^{\circ }$

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