Angle between lines

Calculate the angle between these two lines:

$p: -8x +4y +5 =0$

$q: 10x +10y -7=0$

Result

α =  45 °

Solution:

\alpha = \arctan( \dfrac{|\dfrac{ -8}{ 4}-\dfrac{ 10}{ 10}|}{|1-\dfrac{ -8}{ 4}\cdot \dfrac{ 10}{ 10}|})= 45 \text{ ^\circ }

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