Quadratic equation

Quadratic equation
3x2+bx+c=03x2+bx+c=0



has roots x1 = -26 and x2 = -86. Calculate the coefficients b and c.

Result

b =  336
c =  6708

Solution:

b=3(26+86)=336b = 3 \cdot (26 +86) = 336
c=3(26)(86)=6708  3x2+336x+6708=0 c = 3 \cdot (-26) \cdot (-86) = 6708 \ \\ \ \\ 3x^2 +336x +6708=0 \ \\



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