Quadratic equation

Determine the numbers b, c that the numbers x1 = -1 and x2 = 3 were roots of quadratic equation:

3x2+bx+c=0-3x 2 + b x + c = 0


Result

b =  6
c =  9

Solution:

a=3 b=ax1ax2=6a = -3 \ \\ b = -a x_1 - a x_2 = 6
c=ax1x2=9 3x2+6x+9=0c = a x_1 x_2 = 9 \ \\ -3x ^2 +6x +9 = 0



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