# Roots

Determine the quadratic equation absolute coefficient q, that the equation has a real double root and the root x calculate:

$5x 2 +9x + q = 0$

Result

q =  4.05
x =  -0.9

#### Solution:

$D=0 => D^2=0 \ \\ D^2=b^2-4aq=0 \ \\ q= \dfrac{ 9^2}{4 \cdot 5 } = 4.05 \ \\ 5x ^2 +9x +4.05 = 0$
$x = \dfrac{ -9}{ 2 \cdot 5} = -0.9$

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