Equation with abs value

How many solutions has the equation (x+x)x3=x+1 in the real numbers?

Final Answer:

n =  4

Step-by-step explanation:

(x +x)   x3 = x+1  Z=set(0,3,1)    x  1 (x+x) (x+3)=(x1) 0 (3x) = (x+1) 0 = (x+1) x1=1  .  x2=0.2192235935960.2192 x3=2.28077640642.2808 x4=3.637458608823.6375  n=4



Did you find an error or inaccuracy? Feel free to send us. Thank you!







Tips for related online calculators
Are you looking for help with calculating roots of a quadratic equation?
Do you have a linear equation or system of equations and are looking for its solution? Or do you have a quadratic equation?

You need to know the following knowledge to solve this word math problem:

algebraarithmeticGrade of the word problem

Related math problems and questions: