Equation

Equation 3x2+bx108=0 has one root x1 = 1. Determine the coefficient b and the second root x2.

Final Answer:

b =  111
x2 =  1

Step-by-step explanation:

3 x2+b x 108 =0 c=108 a=3 x1=1  a x2 + b x +c = 0  a x12+b x1+c=0 (3) 12+b 1+(108)=0  b=111
ax2+bx+c=0  (3)x2+111 x+(108)=0 3x2+111x108=0 3x2111x+108=0 3 ...  prime number 111=337 108=2233 GCD(3,111,108)=3  x237x+36=0  a=1;b=37;c=36 D=b24ac=3724136=1225 D>0  x1,2=2ab±D=237±1225 x1,2=237±35 x1,2=18.5±17.5 x1=36 x2=1

Our quadratic equation calculator calculates it.




Did you find an error or inaccuracy? Feel free to send us. Thank you!







Tips for related online calculators
Are you looking for help with calculating roots of a quadratic equation?
Do you have a linear equation or system of equations and are looking for its solution? Or do you have a quadratic equation?

You need to know the following knowledge to solve this word math problem:

algebraGrade of the word problem

Related math problems and questions: