Equation

Equation 3x2+bx108=0 has one root x1 = 1. Determine the coefficient b and the second root x2.

Final Answer:

b =  111
x2 =  1

Step-by-step explanation:

3 x2+b x 108 =0 c=108 a=3 x1=1  a x2 + b x +c = 0  a x12+b x1+c=0 (3) 12+b 1+(108)=0  b=111
ax2+bx+c=0  (3)x2+111 x+(108)=0 3x2+111x108=0 3x2111x+108=0 3 ...  prime number 111=337 108=2233 GCD(3,111,108)=3  x237x+36=0  a=1;b=37;c=36 D=b24ac=3724136=1225 D>0  x1,2=2ab±D=237±1225 x1,2=237±35 x1,2=18.5±17.5 x1=36 x2=1

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