The product of the roots

Find the product and the sum of the roots of x2 + 3x - 9 = 0

Final Answer:

p =  -9
s =  -3

Step-by-step explanation:

x2 + 3x − 9 = 0 a=1 b=3 c=−9  p=c/a=(−9)/1=−9
s=−b/a=−3/1=−3   Verifying Solution:  x2+3x−9=0  x2+3x−9=0  a=1;b=3;c=−9 D=b2−4ac=32−4⋅1⋅(−9)=45 D>0  x1,2​=2a−b±D​​=2−3±45​​=2−3±35​​ x1,2​=−1.5±3.354102 x1​=1.854101966 x2​=−4.854101966  p1​=x1​⋅ x2​=1.8541⋅ (−4.8541)=−9 s1​=x1​+x2​=1.8541+(−4.8541)=−3

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