Dimensions 4118

The width of the rectangle is 17 cm smaller than its length. The perimeter of the rectangle measures 0.9 m. Find the remaining dimensions and calculate their area.

Correct answer:

a =  31 cm
b =  14 cm
S =  434 cm2

Step-by-step explanation:


a=17+b
2(a+b)=90

a=17+b
2·(a+b)=90

a-b = 17
2a+2b = 90

Pivot: Row 1 ↔ Row 2
2a+2b = 90
a-b = 17

Row 2 - 1/2 · Row 1 → Row 2
2a+2b = 90
-2b = -28


b = -28/-2 = 14
a = 90-2b/2 = 90-2 · 14/2 = 31

a = 31
b = 14

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