Four integers

Find four consecutive integers so that the product of the first two is 70 times smaller than the product of the next two.

Correct answer:

a =  16
b =  17
c =  18
d =  19

Step-by-step explanation:

a(a+1) = (a+2) (a+3)  70 a2+a = a2+5a+670 4a = 64 a=64/4=16

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