Four integers

Fnd four consecutive integers so that the product of the first two is 70 times smaller than the product of the next two.

Correct result:

a =  16
b =  17
c =  18
d =  19

Solution:

a(a+1)=(a+2) (a+3)70 a2+a=a2+5a+670 4a=64 a=64/4=16
b=a+1=16+1=17
c=b+1=17+1=18
d=c+1=18+1=19



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