Disjoint

How many elements have union and intersection of two disjoint sets when the first have 1 and secodn 8 elements.

Result

union:  9
intersect:  0

Solution:

n(AB)=n(A)+n(B)=1+8=9n(A \cup B) = n(A)+n(B) = 1+8 = 9
n(AB)=0n(A \cap B) = 0



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