Approximately 4222

The equator is approximately 40,000 km long. What would be the gap between an imaginary hoop 40001 km long and the ground? Would a mouse crawl under it?

Result

x =  159.15 m


x =

Step-by-step explanation:

o1=40000 o2=40001 r1=o1/(2π)=40000/(2 3.1416)6366.1977 r2=o2/(2π)=40001/(2 3.1416)6366.3569 x=1000 (r2r1)=1000 (6366.35696366.1977)=159.15 m
x>10cm



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