Dataset

Data: 11,15,11,16,12,17,13,21,14,21,15,22

Find dispersion of given dataset

Correct answer:

s =  13.8889

Step-by-step explanation:

S=11+15+11+16+12+17+13+21+14+21+15+22=188 m=S/12=188/12=347=153215.6667 s1=(m11)2=(15.666711)2=9196=219721.7778 s2=(m15)2=(15.666715)2=940.4444 s3=(m11)2=(15.666711)2=9196=219721.7778 s4=(m16)2=(15.666716)2=910.1111 s5=(m12)2=(15.666712)2=9121=139413.4444 s6=(m17)2=(15.666717)2=916=1971.7778 s7=(m13)2=(15.666713)2=964=7917.1111 s8=(m21)2=(15.666721)2=9256=289428.4444 s9=(m14)2=(15.666714)2=925=2972.7778 s10=(m21)2=(15.666721)2=9256=289428.4444 s11=(m15)2=(15.666715)2=940.4444 s12=(m22)2=(15.666722)2=9361=409140.1111 s=(s1+s2+s3+s4+s5+s6+s7+s8+s9+s10+s11+s12)/12=(21.7778+0.4444+21.7778+0.1111+13.4444+1.7778+7.1111+28.4444+2.7778+28.4444+0.4444+40.1111)/12=13.8889



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