Dataset

Data: 11,15,11,16,12,17,13,21,14,21,15,22

Find dispersion of a given dataset.

Correct answer:

s =  13.8889

Step-by-step explanation:

S=11+15+11+16+12+17+13+21+14+21+15+22=188 m=S/12=188/12=347​=1532​≐15.6667 s1​=(m−11)2=(15.6667−11)2=9196​=2197​≐21.7778 s2​=(m−15)2=(15.6667−15)2=94​≐0.4444 s3​=(m−11)2=(15.6667−11)2=9196​=2197​≐21.7778 s4​=(m−16)2=(15.6667−16)2=91​≐0.1111 s5​=(m−12)2=(15.6667−12)2=9121​=1394​≐13.4444 s6​=(m−17)2=(15.6667−17)2=916​=197​≐1.7778 s7​=(m−13)2=(15.6667−13)2=964​=791​≐7.1111 s8​=(m−21)2=(15.6667−21)2=9256​=2894​≐28.4444 s9​=(m−14)2=(15.6667−14)2=925​=297​≐2.7778 s10​=(m−21)2=(15.6667−21)2=9256​=2894​≐28.4444 s11​=(m−15)2=(15.6667−15)2=94​≐0.4444 s12​=(m−22)2=(15.6667−22)2=9361​=4091​≐40.1111 s=(s1​+s2​+s3​+s4​+s5​+s6​+s7​+s8​+s9​+s10​+s11​+s12​)/12=(21.7778+0.4444+21.7778+0.1111+13.4444+1.7778+7.1111+28.4444+2.7778+28.4444+0.4444+40.1111)/12=13.8889

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