# Digit sum

Determine for how many integers greater than 900 and less than 1,001 has digit sum digit of the digit sum number 1.

Result

n =  1

#### Solution:

$c=1000 \ \\ c_{ 1 }=C(1000)=1+0+0+0=1 \ \\ c_{ 2 }=C(c_{ 1 })=1 \ \\ n=1$

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