Everyone 4572

Two workers completed the work in 12 days. If the other worked ten days longer than the first, how long would everyone work alone?

Correct answer:

a =  -6 d
b =  4 d

Step-by-step explanation:

1/a+1/b=1/12 b = 10+a 1/a+1/(10+a)=1/12 10+a+a=1/12 (10+a) a  10+a+a=1/12 (10+a) a 0.083333333333332a2+1.167a+10=0 0.083333333333332a21.167a10=0  p=0.083333;q=1.167;r=10 D=q24pr=1.167240.083333(10)=4.6944444444 D>0  a1,2=2pq±D=0.1666671.17±4.69 a1,2=7±13 a1=20 a2=6 a>0 a=a2=(6)=6 d

Our quadratic equation calculator calculates it.

b=10+a=10+(6)=4=4 d x=12 (1/a+1/b)=12 (1/(6)+1/4)=1



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