# Working together

Two people will do the work in 12 days. They worked together for 8 days. Then only one worked for 10 days. How many days would each of them do the work if he worked alone?

Result

x =  12 d
a =  30 d
b =  20 d

#### Solution:

$12/a+12/b=1 \ \\ 8/a+8/b + 10/a=1 \ \\ \ \\ a=30 \ \\ b=20 \ \\ \ \\ x=12 \ \text{d}$
$a=30 \ \text{d}$
$b=20 \ \text{d}$

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