Ladder 8 m long is leaning against the wall. Its foot is 1 m away from the wall. In which height ladder touches the wall?

Result

d =  7.9 m

Solution:

$x=8 \ \text{m} \ \\ y=1 \ \text{m} \ \\ d=\sqrt{ x^{ 2 }-y^{ 2 } }=\sqrt{ 8^{ 2 }-1^{ 2 } } \doteq 3 \ \sqrt{ 7 } \doteq 7.9373 \doteq 7.9 \ \text{m}$

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