Calculate

Calculate the height to the base of the isosceles triangle ABC if the length of the base is c = 24cm and the arms have a length b = 13cm.

Correct answer:

v =  5 cm

Step-by-step explanation:

$$\begin{gathered} c=24\text{ cm } \\ b=13\text{ cm } \\ {b}^2=v^2+(c\mathrm{/}2{)}^2 \\ v=\sqrt{b^2-(c\mathrm{/}2{)}^2}=\sqrt{13^2-(24\mathrm{/}2{)}^2}=5\text{ cm} \end{gathered}$$

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