# Two aircraft

From the airport will start simultaneously two planes, which fly tracks are perpendicular to each other. The first flying speed of 680 km/h and the second 840 km/h. Calculate how far the aircraft will fly for half an hour.

Result

s =  540 km

#### Solution:

$v_{1}=680 \ \\ v_{2}=840 \ \\ t=0.5 \ \\ s_{1}=v_{1} \cdot \ t=680 \cdot \ 0.5=340 \ \\ s_{2}=v_{2} \cdot \ t=840 \cdot \ 0.5=420 \ \\ s=\sqrt{ s_{1}^2+s_{2}^2 }=\sqrt{ 340^2+420^2 } \doteq 20 \ \sqrt{ 730 } \doteq 540.3702 \doteq 540 \ \text{km}$

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