Quadratic inequation

If 5x + x² > 100, then x is not

Correct answer:

x =  0

Step-by-step explanation:

5x+x2100=0  x2+5x100=0  a=1;b=5;c=100 D=b24ac=5241(100)=425 D>0  x1,2=2ab±D=25±425=25±517 x1,2=2.5±10.307764 x1=7.807764064 x2=12.807764064 x>x1 x=x<x2=0

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Showing 1 comment:
Math student
x not in interval <-12.807764064; 7.80776406404>

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