Quadratic inequation

If 5x + x² > 100, then x is not

Correct result:

x =  0

Solution:

5x+x2100=0  5x+x2100=0 x2+5x100=0  a=1;b=5;c=100 D=b24ac=5241(100)=425 D>0  x1,2=b±D2a=5±4252=5±5172 x1,2=2.5±10.307764064 x1=7.80776406404 x2=12.807764064   Factored form of the equation:  (x7.80776406404)(x+12.807764064)=0 x>x1 x=x<x2=0

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Math student
x not in interval <-12.807764064; 7.80776406404>

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