Bags

The first bag has a weight of 18 kg, the second bag is a one-third lighter than the first and the third bag has three times less the weight of all three bags together. Determine their weights.

Correct result:

a =  18 kg
b =  12 kg
c =  15 kg

Solution:

$a=18=18\text{ kg}$

$b=a-a\mathrm{/}3=18-18\mathrm{/}3=12\text{ kg}$

c = (18+12+c)/3

2c = 30

c = 15

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