# Bags

The first bag has a weight of 18 kg, the second bag is a one-third lighter than the first and the third bag has three times less the weight of all three bags together. Determine their weights.

Result

a =  18 kg
b =  12 kg
c =  15 kg

#### Solution:

$a = 18 = 18 \ \text{ kg }$
$b = a - a/3 = 18 - 18/3 = 12 = 12 \ \text{ kg }$

c = (18+12+c)/3

2c = 30

c = 15

Calculated by our simple equation calculator.

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