Isosceles trapezoid

Find the height in an isosceles trapezoid if the area is 520 cm2 and the base a = 25 cm and c = 14 cm. Calculate the interior angles of the trapezoid.

Correct answer:

h =  26.6667 cm
A =  78.3462 °
B =  78.3462 °
C =  101.6538 °
D =  101.6538 °

Step-by-step explanation:

a=25 cm c=14 cm S=520 cm2  S=a+c2 h  h=2 Sa+c=2 52025+14=803 cm=26.6667 cm
x=(ac)/2=(2514)/2=112=5.5 cm  tanA=h:x  A=180°πarctan(h/x)=180°πarctan(26.6667/5.5)=78.3462°=78°2046"
B=A=78.3462=78.3462°=78°2046"
C=180B=18078.3462=101.6538°=101°3914"
D=180A=18078.3462=101.6538°=101°3914"



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