# Isosceles trapezoid

Find the height in an isosceles trapezoid if the area is 520 cm2 and the base a = 25 cm and c = 14 cm. Calculate the interior angles of the trapezoid.

h =  26.6667 cm
A =  78.3462 °
B =  78.3462 °
C =  101.6538 °
D =  101.6538 °

### Step-by-step explanation:

$B=A=78.3462=78.346{2}^{\circ }=7{8}^{\circ }2{0}^{\mathrm{\prime }}46\mathrm{"}$
$C=180-B=180-78.3462=101.653{8}^{\circ }=10{1}^{\circ }3{9}^{\mathrm{\prime }}14\mathrm{"}$
$D=180-A=180-78.3462=101.653{8}^{\circ }=10{1}^{\circ }3{9}^{\mathrm{\prime }}14\mathrm{"}$

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