Isosceles trapezoid

Find the height in an isosceles trapezoid if the area is 520 cm² and the base a = 25 cm and c = 14 cm. Calculate the interior angles of the trapezoid.

Final Answer:

h =  26.6667 cm
A =  78.3462 °
B =  78.3462 °
C =  101.6538 °
D =  101.6538 °

Step-by-step explanation:

a=25 cm c=14 cm S=520 cm2  S = 2a+c h  h=a+c2 S=25+142 520=380 cm=26.6667 cm
x=(ac)/2=(2514)/2=211=5.5 cm  tan A = h : x  A=π180°arctan(h/x)=π180°arctan(26.6667/5.5)=78.3462=78°2046"
B=A=78.3462=78.3462=78°2046"
C=180B=18078.3462=101.6538=101°3914"
D=180A=18078.3462=101.6538=101°3914"



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