Trapezoid 82216

Given is an isosceles trapezoid ABCD with bases 10 cm and 14 cm. The height of the trapezoid is 6 cm. Determine the interior angles of the trapezoid.

Correct answer:

α =  71.5651 °
β =  71.5651 °
γ =  108.4349 °
δ =  108.4349 °

Step-by-step explanation:

$\beta =\alpha =71.5651=71.5651^{\circ }=71°33^{\prime }54"$

$\gamma =180-\beta =180-71.5651=108.4349^{\circ }=108°26^{\prime }6"$

$\delta =\gamma =108.4349=108.4349^{\circ }=108°26^{\prime }6"$

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