Suspended 48691

A body weighing 400 kg is suspended at a distance of 1 m from one end of the beam on a beam weighing 100 kg and 5 m. How large do forces act at the ends of the beam?

Correct answer:

F1 =  3700 N
F2 =  1300 N

Step-by-step explanation:

g=10 m/s2 m1=100 kg l=5 m x=1 m m2=400 kg  G1=m1 g=100 10=1000 N G2=g m2=10 400=4000 N  a+b=G2 a x=b (lx) a+b=4000 a 1=b (51)  a+b=4000 a4b=0  a=3200 b=800  F1=a+G1/2=3200+1000/2=3700 N
F2=b+G1/2=800+1000/2=1300 N



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