A shopkeeper 3

A shopkeeper sells 8 1/3 kg, 10 1/4 kg and 11 1/5 kg of apples on 3 consecutive days. What is the total weight of apples sold?

Correct answer:

x =  19.5333 kg

Step-by-step explanation:

$$\begin{gathered} a=8{\displaystyle \frac{1}{3}}=8+{\displaystyle \frac{1}{3}}={\displaystyle \frac{8\cdot 3+1}{3}}={\displaystyle \frac{25}{3}}\doteq 8.3333\text{ kg } \\ b=10{\displaystyle \frac{1}{4}}=11+{\displaystyle \frac{1}{5}}={\displaystyle \frac{11\cdot 5+1}{5}}={\displaystyle \frac{56}{5}}=11.2\text{ kg } \\ b=11{\displaystyle \frac{1}{5}}=11+{\displaystyle \frac{1}{5}}={\displaystyle \frac{11\cdot 5+1}{5}}={\displaystyle \frac{56}{5}}=11.2\text{ kg } \\ x=a+b+c=8.3333+11.2+c={\displaystyle \frac{293}{15}}\text{ kg}=19\frac{8}{15}\text{ kg}=19.5333\text{ kg} \end{gathered}$$

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