Golf ball

When a golf ball is hit with two iron, it rotates at a rate of 8 1/3 times/second. How many times does this ball rotate if it is airborne for 7 1/3 seconds?

Correct answer:

n =  61 ¹⁄₉ = 550/9

Step-by-step explanation:

$$\begin{gathered} v=8\frac{1}{3}=8+\frac{1}{3}=\frac{8\cdot 3+1}{3}=\frac{24+1}{3}=\frac{25}{3}=8\frac{1}{3}\doteq 8.3333\text{rps} \\ t=7\frac{1}{3}=7+\frac{1}{3}=\frac{7\cdot 3+1}{3}=\frac{21+1}{3}=\frac{22}{3}=7\frac{1}{3}\doteq 7.3333\text{s} \\ n=v\cdot t=\frac{25}{3}\cdot \frac{22}{3}=\frac{25\cdot 22}{3\cdot 3}=\frac{550}{9}=61\frac{1}{9}=61.1111 \end{gathered}$$

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