Golf ball

When a golf ball is hit with a 2 iron, it rotates at a rate of 8 1/3 times/second. How many times does this ball rotate if it is airborn for 7 1/3 seconds

Correct answer:

n =  61.1111

Step-by-step explanation:

$$\begin{gathered} v=8{\displaystyle \frac{1}{3}}=8+{\displaystyle \frac{1}{3}}={\displaystyle \frac{8\cdot 3+1}{3}}={\displaystyle \frac{25}{3}}\doteq 8.3333\text{ rps } \\ t=7{\displaystyle \frac{1}{3}}=7+{\displaystyle \frac{1}{3}}={\displaystyle \frac{7\cdot 3+1}{3}}={\displaystyle \frac{22}{3}}\doteq 7.3333\text{ s } \\ n=v\cdot t=8.3333\cdot 7.3333={\displaystyle \frac{550}{9}}=61\frac{1}{9}=61.1111 \end{gathered}$$

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