# Rhombus construction

Construct ABCD rhombus if its diagonal AC=9 cm and side AB = 6 cm. Inscribe a circle in it touching all sides...

### Correct answer:

**Showing 2 comments:**

**Dr Math**

1. draw line segment AB = 6 cm

2. draw circle k1 (B, r=6 cm)

2. draw circle k2 (A, r=9 cm)

4. point C is intersect k1 and k2

5. draw line u2 from B perpendicular to AC

6. draw circle k3 (A, r=6 cm)

7. point D is intersect k3 and line u2

8. connect points ABCD to rhombus

9. point S is intersect of AC diagonal and BD diagonal

10. make perpendicular line u3 from S to AB.

11. draw inswribed circle with center S and radius SX, X is intersection of u3 and AB

2. draw circle k1 (B, r=6 cm)

2. draw circle k2 (A, r=9 cm)

4. point C is intersect k1 and k2

5. draw line u2 from B perpendicular to AC

6. draw circle k3 (A, r=6 cm)

7. point D is intersect k3 and line u2

8. connect points ABCD to rhombus

9. point S is intersect of AC diagonal and BD diagonal

10. make perpendicular line u3 from S to AB.

11. draw inswribed circle with center S and radius SX, X is intersection of u3 and AB

**Dr Math**

another steps:

1. Draw AC = 9cm horizontally.

2. With A as center and AB =6cm as radius, draw arcs above and below AC.

3. With C as center and AB as radius, draw arcs to cut the earlier arcs.

4. Intersection points are B and D.

5. Join all sides.

6. Draw BD. The intersection of AC AND BD is O , the center of the incircle.

7. Draw an arc with O as center and OB as radius to cut BC at E.

8. Draw perpendicular bisector of BE. It passes through O. Mid point of BE is F.

9. OF as radius and O as center draw the incircle.

1. Draw AC = 9cm horizontally.

2. With A as center and AB =6cm as radius, draw arcs above and below AC.

3. With C as center and AB as radius, draw arcs to cut the earlier arcs.

4. Intersection points are B and D.

5. Join all sides.

6. Draw BD. The intersection of AC AND BD is O , the center of the incircle.

7. Draw an arc with O as center and OB as radius to cut BC at E.

8. Draw perpendicular bisector of BE. It passes through O. Mid point of BE is F.

9. OF as radius and O as center draw the incircle.

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