Diagonals in diamons/rhombus

Rhombus ABCD has side length AB = 4 cm and a length of one diagonal of 6.4 cm. Calculate the length of the other diagonal.

Correct result:

u2 =  4.8 cm

Solution:

a=4 u1=6.4 a2=(u1/2)2+(u2/2)2 u2=2⋅ a2−(u1/2)2=2⋅ 42−(6.4/2)2=245=245 cm=4.8 cm

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