Weight fraction

To prepare the brine, we need 1500 g of an aqueous salt solution with a weight fraction of 0.08. What weight of salt and volume of water do we need to prepare it?

Correct answer:

m1 =  120 g
V2 =  1.38 l

Step-by-step explanation:

m=1500 g  m1:m=0.08  m1=m 0.08=1500 0.08=120 g
m2=mm1=1500120=1380 g ρ2=1000 g/l  ρ2=m2/V2 V2=m2/ρ2=1380/1000=5069 l=1.38 l

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