Serial resistors

In the circuit shown ( two resistiors R1 and R2 serial connected), the total resistance from A to B is 16 ohms. Find the resistance R2 and the current through the R1 = 12-Ohm resistor, if voltage between A and B is 10 V.

Correct answer:

R2 =  4 Ω
I =  0.625 A

Step-by-step explanation:

R1=12 Ω R=16 Ω  R=R1+R2  R2=RR1=1612=4 Ω
U=10 V  I=U/R=10/16=0.625 A



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