Serial resistors

In the circuit shown ( two resistors, R1 and R2, serially connected), the total resistance from A to B is 16 ohms. If the voltage between A and B is 10 V, find the resistance R2 and the current through the R1 = 12-ohm resistor.

Final Answer:

R₂ =  4 Ω
I =  0.625 A

Step-by-step explanation:

$$\begin{gathered} R_1=12\Omega \\ R=16\Omega \\ R=R_1+R_2 \\ {R}_2=R-R_1=16-12=4\Omega \end{gathered}$$

$$\begin{gathered} U=10\text{V} \\ I=U/R=10/16=0.625\text{A} \end{gathered}$$

Try another example