Tetrahedron

What is the angle of the sides from the base of a three-sided pyramid where the sides are identical?

Correct result:

A =  54.7356 °

Solution:

a=1 h1=a2−(a/2)2=12−(1/2)2≐0.866 x=23⋅ h1=23⋅ 0.866≐0.5774 cos⁡(A)=x/a A=180∘π⋅arccos⁡(x/a)=180∘π⋅arccos⁡(0.5774/1)=54.7356∘=54∘44′8"

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