Tetrahedral pyramid

What is the surface of a regular tetrahedral (four-sided) pyramid if the base edge a=16 and height v=16?

Correct answer:

S =  828.4

Step-by-step explanation:

a=16 v=16  w1=v2+(2a)2=162+(216)2=8 517.8885  S1=a2=162=256  S2=2a w1=216 17.8885=64 5143.1084  S=S1+4 S2=256+4 143.1084=828.4

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Tips for related online calculators
The Pythagorean theorem is the base for the right triangle calculator.
See also our trigonometric triangle calculator.

We encourage you to watch this tutorial video on this math problem: video1   video2

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