Equilateral tetrahedral pyramid

The base edge of a regular tetrahedral pyramid is a = 4 cm. base and walls are equilateral. Calculate the surface of this pyramid.

Correct answer:

S =  27.7128 dm2

Step-by-step explanation:

a=4 cm  h=3/2 a=3/2 4=2 3 cm3.4641 cm  S1=a h/2=4 3.4641/2=4 36.9282  S=4 S1=4 6.9282=16 3=27.7128 dm2



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