4s pyramid

Regular tetrahedral pyramid has a base edge a=17 and collaterally edge length b=32.

What is its height?

Result

v =  29.66

Solution:

u1=2a v=b2u124=b2a22=3221722=29.66u_1 = \sqrt2 a \ \\ v = \sqrt{ b^2 -\dfrac{ u_1^2}{4}} = \sqrt{ b^2 -\dfrac{ a^2}{2}} = \sqrt{ 32^2 -\dfrac{ 17^2}{2}} = 29.66



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