Church roof

The roof of the church tower has the shape of a regular tetrahedral pyramid with base edge length 5.4 meters and a height 5 m. It was found that needs to be corrected 27% covering of the roof area. What amount of material will be required?

Correct result:

S =  16.57 m2

Solution:

a=5.4 h=5 h2=h2+(a/2)2=52+(5.4/2)25.6824 S1=a h2/2=5.4 5.6824/215.3426 S2=4 S1=4 15.342661.3702 S=S2 27/100=61.3702 27/100=16.57 m2



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