Pyramid roof

2/4 of the area of ​​the roof-shaped regular tetrahedral pyramid with base edge 10 m and height of 4 m is already covered with roofing. How many square meters still need to be covered?

Correct answer:

S =  64.0312 m2

Step-by-step explanation:

a=10 h=4 q=12/4=21=0.5 h1=h2+(a/2)2=42+(10/2)2=416.4031 S1=a h1/2=10 6.4031/2=5 4132.0156 S=q 4 S1=0.5 4 32.0156=10 41=64.0312 m2

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Tips to related online calculators
Pythagorean theorem is the base for the right triangle calculator.
See also our trigonometric triangle calculator.

We encourage you to watch this tutorial video on this math problem: video1   video2

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