Pyramid roof

2/4 of the area of ​​the roof-shaped regular tetrahedral pyramid with base edge 10 m and height of 4 m is already covered with roofing. How many square meters still need to be covered?

Correct answer:

S =  64.0312 m2

Step-by-step explanation:

a=10 h=4 q=12/4=21=0.5 h1=h2+(a/2)2=42+(10/2)2=416.4031 S1=a h1/2=10 6.4031/2=5 4132.0156 S=q 4 S1=0.5 4 32.0156=10 41=64.0312 m2



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